3x^2+48-780=0

Solution for 3x^2+48-780=0 equation:

3x^2+48-780=0

We add all the numbers together, and all the variables

3x^2-732=0

a = 3; b = 0; c = -732;
Δ = b2-4ac
Δ = 02-4·3·(-732)
Δ = 8784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8784}=\sqrt{144*61}=\sqrt{144}*\sqrt{61}=12\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{61}}{2*3}=\frac{0-12\sqrt{61}}{6}
=-\frac{12\sqrt{61}}{6}
=-2\sqrt{61}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{61}}{2*3}=\frac{0+12\sqrt{61}}{6}
=\frac{12\sqrt{61}}{6}
=2\sqrt{61}
$